Board 13 was a push. I'm up 12 imps with three boards left in the match.
Board 14
Neither vulnerable
♠ Q 4 ♥ K Q 10 7 6 ♦ A K 8 ♣ K Q 5 |
RHO passes. I open with one heart and partner bids one spade.
Had partner responded with one notrump, I would raise to three. Two notrump should show 17-18 HCP, and you should drive to game with 19. But after a one-spade response, the range of two notrump should be extended to include 19 HCP.
There are two reasons for this: For one, we may belong in four spades, something you needn't worry about after one-notrump. If you rebid three notrump, partner, with five spades, has no way to check for three-card support. And, even with six, he will be wary of correcting, since you could be bidding three notrump with a stiff spade and solid hearts. Another reason is that two notrump keeps the auction low in case partner has a good hand and wants to investigate slam. Again, that isn't a concern when partner is limited.
I rebid two notrump. Partner raises to three, and LHO leads the king of spades.
NORTH Robot ♠ 10 6 5 3 2 ♥ A 5 ♦ Q J 10 7 4 2 ♣ -- |
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SOUTH Phillip ♠ Q 4 ♥ K Q 10 7 6 ♦ A K 8 ♣ K Q 5 |
West | North | East | South |
Robot | Robot | Robot | Phillip |
Pass | 1 ♥ | ||
Pass | 1 ♠ | Pass | 2 NT |
Pass | 3 NT | (All pass) |
Three notrump! Why not three diamonds? Not only could we have a five-three spade, but, even if we don't, we could be going down in three notrump cold for a diamond game. Or even a diamond slam, though I'm not sure how we could get there intelligently.
Fortunately I have a doubleton spade and good clubs, so three notrump is the right spot. East plays the spade seven; I play the four. West shifts to the deuce of hearts. I win and play a heart to the ace. Hearts split, so I claim eleven tricks.
NORTH Robot ♠ 10 6 5 3 2 ♥ A 5 ♦ Q J 10 7 4 2 ♣ -- |
||
WEST Robot ♠ A K J ♥ J 9 2 ♦ 9 6 3 ♣ A J 8 6 |
EAST Robot ♠ 9 8 7 ♥ 8 4 3 ♦ 5 ♣ 10 9 7 4 3 2 |
|
SOUTH Phillip ♠ Q 4 ♥ K Q 10 7 6 ♦ A K 8 ♣ K Q 5 |
West's heart shift was a nice play. If I have ace-king tight of diamonds, it tangles up my entries. If I hold,
♠ Q x x ♥ K 10 x x x ♦ A K ♣ K Q x, |
the heart shift beats me. Even if you add the queen of hearts to my hand, a heart shift stops the overtricks.
I have one question I hope someone can answer. Since my contract was safe, after winning the heart ace, I could have played a spade and conceded two overtricks to score the beer card. Is the beer card worth two imps? I don't drink beer, so I don't know.
This board is probably another push. You can check out Jazlene's play at JazPlaysBridge to verify.
Board 14 was quick, so I'll offer a bonus. This was a fun deal I played this morning in the Zenith Daylong:
NORTH Phillip ♠ 10 6 3 ♥ 8 ♦ K J 3 ♣ A K J 10 8 6 |
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SOUTH Robot ♠ K 4 ♥ A J 6 4 2 ♦ 10 6 5 4 2 ♣ Q |
West | North | East | South |
Robot | Phillip | Robot | Robot |
1 ♣ | 1 ♠ | 2 ♥ | |
2 ♠ | 3 ♣ | Pass | 3 ♦ |
Pass | 3 ♠ | Pass | 3 NT |
(All pass) |
West leads the spade four. East wins with the ace and returns the queen of spades to my king as West plays the nine.
I have eight tricks. Reese says where there are eight tricks, there are nine. Is he right on this deal? The opponents have five tricks--four spades and the diamond ace. If I can squeeze East out of a spade, they have only four. Then perhaps I can then set up a diamond trick.
Unless East has king-queen of hearts and the diamond ace, I don't see how I can squeeze him. And if he has all that, it leaves West with nothing for his spade raise. But it doesn't hurt to run clubs and see what happens.
I overtake the club queen and start the club suit, pitching a heart and a diamond. Everyone follows to the first two clubs. On the third club, East pitches the deuce of spades. He pitched a spade already? He knows he has to come down to five cards, and he has decided that they can't include three spades. What can he have to reach that conclusion? If he had the diamond ace, surely he would plan to come down to three spades, the ace of diamonds, and a heart and hope his partner can stop the heart suit. If he thinks he needs to pitch a spade, the ace of diamonds must be on my left.
What should I discard? I need someone to come down to a stiff ace or queen of diamonds, so I want to make it dangerous for the opponents to pitch hearts. That means I need to keep my hearts. I pitch another diamond.
I cash another club. East pitches the seven of hearts, and I pitch another diamond. West pitches the nine of hearts.
The robots tend to pitch count cards. So it appears West has four hearts and East began with honor-ten-seven. That means East is 5-3-3-2 and West is 3-4-2-4. If I've read the deal correctly, this should be the current position, with the lead in dummy:
NORTH Phillip ♠ 10 ♥ 8 ♦ K J 3 ♣ 6 |
||
WEST Robot ♠ x ♥ ? x x ♦ A ? ♣ -- |
EAST Robot ♠ J x ♥ ? ♦ ? x x ♣ -- |
|
SOUTH Robot ♠ -- ♥ A J 6 4 ♦ 10 6 ♣ -- |
On the last club, East pitches the seven of diamonds. I pitch a diamond, and West pitches the nine of diamonds. West apparently has queen third of hearts left and is afraid I have ace-king, so he stiffed his diamond ace. I exit with a small diamond from dummy. The defense takes a diamond and two spades, and I take the last two tricks. Making three.
NORTH Phillip ♠ 10 6 3 ♥ 8 ♦ K J 3 ♣ A K J 10 8 6 |
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WEST Robot ♠ 9 8 5 ♥ Q 9 5 3 ♦ A 9 ♣ 9 5 4 2 |
EAST Robot ♠ A Q J 7 2 ♥ K 10 7 ♦ Q 8 7 ♣ 7 3 |
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SOUTH Robot ♠ K 4 ♥ A J 6 4 2 ♦ 10 6 5 4 2 ♣ Q |
The key to this deal is realizing East's spade pitch marks the diamond ace in the West hand. I'm compiling a list of rules for card-reading, and I'm adding this one: "The defender who pitches winners in notrump doesn't hold the missing ace."
Most of the rules in my list, like this one, are obvious when you think about it. But they can be surprisingly easy to miss at the table when you have lots of things to think about. It helps to have them formulated ahead of time, so they become second nature.