Sunday, October 12, 2025

Free Weekly Instant Tournament - September 19 - Board 3

 

Board 3
Opponents vulnerable

♠ J 3   A Q 8 6 4   A Q 8 5 3  ♣ 6  

If you prefer, you can watch Alex take you through Board 3 on Gargoyle's YouTube channel:

I open with one heart in first seat. LHO overcalls with two clubs. Partner raises to two hearts. And RHO bids three clubs. Partner's perfect minimum is king third in both red suits, which makes four hearts cold on normal breaks. So my hand is worth an invitation. 

I suspect the field won't be inviting. I would count this as 15 total points after the raise, which isn't worth an invitation. But point count undervalues concentrated strength.

The loser-counters, however, might go to the other extreme and blast game. Five losers, in theory, is worth a four-heart bid. They're wrong, too, in my opinion. Loser count overvalues hands where fit is important. In general, when some people will be content with a part score and others will be blasting game, the baby-bear approach is usually right.

I bid three diamonds, and partner accepts with four hearts. Everyone passes and LHO leads the jack of clubs.

NORTH
Robot
♠ 5 4 2
K 10 9 7
10 7 4 2
♣ A Q
♣ J
SOUTH
Phillip
♠ J 3
A Q 8 6 4
A Q 8 5 3
♣ 6

West North East South
Robot Robot Robot Phillip
1
2 ♣ 2 3 ♣ 3
Pass 4 (All pass)

Since I think a fair percentage of the field will not reach game, my primary concern is making this. So what's my best chance? Should I take the club finesse to pitch a spade?

A vulnerable two-level overcall on a jack-high suit is unlikely, but it's not unheard of. And I might not need the club finesse. If I can take four diamond tricks, I can afford to lose two spades.

I can take four diamond tricks any time diamonds are two-two, which is 40% of the time. 50% of the time they will split three-one one way or the other. Of the eight ways they can split three-one, I can pick up stiff king or jack in either hand. So that's an additional 25%, bringing my total chances up to 65%. 

Actually, I'm wrong. It's better than that. West probably would have led a stiff small or stiff jack of diamonds. So that reduces the denominator. Let's try this again.

If we eliminate the likely diamond leads, we come up with the following table. For each of West's possible holdings, the tables shows whether we can achieve our goal. If we go up with the club ace, our goal is four tricks. If we finesse and it loses, we need five tricks.

Diamond Layout

WestEastCases 4 tricks5 tricks
-- K J x x1
K J x x1Y
K J x x1Y
K x J x2Y
J x K x2YY
x x K J1YY
K x x J1Y
K J x x2
J x x K1Y
K J x x --1

Now we can calculate out chance of success. The percentages aren't exact, because the cases are not equally likely. But it's a good approximation.

GoalCasesPercentage
4 tricks9 / 130.69
5 tricks3 / 130.23

If I go up with the ace, I'll make 69% of the time. What if I finesse? I'll make if the finesse works. I'll make even if the finesse loses if I can take five diamond tricks. If I judge the finesse to be 60%, then finessing works 60% of the time plus 23% of the remaining 40%, or about 69% of the time total. So that's the over-under. If I think the finesse is better than 60%, I should finesse. If not, I should go up.

60% sounds conservative to me. So I'll take over. I play the queen. East plays the three. I pitch a spade on the ace of clubs. East plays the seven; West, the deuce. I play the ten of hearts to my ace to guard against a four-one break. Deuce from East; three from West.

I want to make sure I end up in dummy after the third round of hearts, so I cash the queen next. West discards the seven of spades. I unblock the nine to stay flexible. Now a heart to dummy's king. West discards the king of clubs. I've reached this position with the lead in dummy.

NORTH
Robot
♠ 5 4 2
7
10 7 4 2
♣ --
SOUTH
Phillip
♠ J
8 6
A Q 8 5 3
♣ --

As long as I don't lose three diamond tricks, I've made this. I play the deuce of diamonds from dummy. East plays the six.

My instincts say to cover with the eight. Now I can't go down. If I play the queen... Oh, I still can't go down. If West shows out, I lose a spade and two diamonds. This is why I don't listen to my instincts.

I play the queen. West wins with the king and returns the nine. I claim eleven tricks.

NORTH
Robot
♠ 5 4 2
K 10 9 7
10 7 4 2
♣ A Q
WEST
Robot
♠ K 9 7 6
3
K 9
♣ K J 10 9 8 2
EAST
Robot
♠ A Q 10 8
J 5 2
J 6
♣ 7 5 4 3
SOUTH
Phillip
♠ J 3
A Q 8 6 4
A Q 8 5 3
♣ 6

Plus 650 is worth 100%. I was right the field didn't try for game. Only two other pairs reached game, and they both made only four. 

In retrospect, I missed a key inference in my analysis. I said that if the club finesse lost, I had a 23% chance of taking five diamonds tricks. But that's not true. Given West's failure to lead a spade, the best he can have in spades is ace-queen. If he's missing the club king, that doesn't leave him with much for his overcall. If the club finesse loses, the diamond king is almost surely offside.

That means the over-under for taking the finesse is 69%, not 60. I think I'd still take over. But it's a lot closer.

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